calculate the height of communication satellite

Question

rvc · Answer

$$given\G=6.67\times10^{-11} Nm ^{2}/kg ^{2}\\M=6\times10^{24}kg\\R=6400km$$

rvc · Answer

@paki

paki · Answer

please have a look here....

rvc · Answer

yes

anonymous · Answer

I'm thinking that the essential point is that the comms satellite is in geosynchronous orbit (ie it is always above the same point on the earth's surface)
That tells you what the angular velocity of the satellite must be. (One complete rotation per day)
Then you just have to equate the attraction due to gravity with the centripetal force to find the distance of the satellite from the centre of the earth.

anonymous · Answer

To calculate a really accurate value, give some thought to the definition of 'day' in the above, and how many seconds it contains.