Can you tell me why I got these 3 problems wrong for a medal?
Here's a graphing calculator if anyone needs it: https://www.desmos.com/calculator
For the first one, when you plug in 3 into the equation, it equals 8, which is not <8.
Do you see it?
Also, for the second one, what happens when you take the absolute value of any number?
It is positive correct?
Correct! Now, knowing that whatever is in there, the outcome will ALWAYS be positive, meaning it can't be?..
and yes I do see what I did wrong on the first one. It was a simple addition error on my part.
one moment
No prob bob, take your time.
b cannot be less than zero, so C?
Correct!
For the last one, let me type out the algebraic process
y < x^3 -4x^2 +2 0 < (1)^3 -4(1)^2 +2 0 < 1 -4^2 +2 0 < 1 +16 +2 0 < 19 which is true, or did I do something wrong again?
Yes, you see, the power is not attached to the "4", its attached to the "1".
Ah. I see now.
The power is attached to the "x" in "4x"
So, when you work it out, eventually you get 0<-1 , which is false.
Oh okay. I understand now. Thank you so much for your help! :D
No prob bob. If you need any more assistance, feel free to ask.
Will do. :)
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