Question

graph (x-1)^2/25-(y+2)^2/9=1

Answer 1

do you realize this a hyperbola?

Answer 2

yes

Answer 3

hint \(\bf \cfrac{(x-{\color{brown}{ h}})^2}{{\color{blue}{ a}}^2}-\cfrac{(y-{\color{brown}{ k}})^2}{{\color{blue}{ b}}^2}=1
\\ \quad \\
\cfrac{(x-1)^2}{25}+\cfrac{(y+2)^2}{9}=1\implies \cfrac{(x-{\color{brown}{ 1}})^2}{{\color{blue}{ 5}}^2}-\cfrac{(y{\color{brown}{ +2}})^2}{{\color{blue}{ 3}}^2}=1\)

Answer 4

get the center of it
and use the traversal and conjugate axes to draw it
bear in mind that the "positive fraction" variable is the axis where the hyperbola opens towards

Answer 5

center is (1, -2) ?

Answer 6

yeap center is 1,-2

traverse axis is "positive fraction" denominator.. .. so is 5
conjugate axis is 3

Answer 7

so vertices are (6,-2) and (-4,-2)
do i graph at these?

Answer 8

well... yes.. you need the vertices to start the draw from and outwards

Answer 9

okay thanks

Answer 10

notice the co-vertices are (-2,1) and (-2, -4)