Question

Find an equation of the tangent line to the graph at the given point.
(x + 2)^2 + (y − 3)^2 = 37, (−1, −3)

i got -(x+2)/(y-3) and when i plug in for x and y i got (y+3)=1/6(x+1)
but it keeps saying my answer is wrong what am i doing wrong

Answer 1

what is dy/dx?

Answer 2

-(x+2)/(y-3)

Answer 3

thats what i got for the dy/dx and then when i plug in points i got (y+3)=1/6(x+1) but it said thats wrong

Answer 4

so what is dy/dx, meaning what does it represent?

Answer 5

you use dy/dx when you take the derivative of y

Answer 6

i know how to take derivatives and all and i know the answer i got was correct for the dy/dx because i check on multiple sights like alpha and all and came out with same answer i got so i have to somehow made a mistake plugging in

Answer 7

\[\frac{ dy }{ dx }=\frac{ \Delta y }{ \Delta x }\]

Answer 8

it's the slope... you have to use the point to get the slope at that point.
then use the slope and the point in the point-slope form.

Answer 9

you may have taken the derivative correctly but your interpretation and how you are using it is not correct.

Answer 10

so how is (y+3)=1/6(x+1) not right because i been using the same form on every other problem i been doing this way and that form was right

Answer 11

im confused lol

Answer 12

slope at (-1, -3)

Answer 13

\[\frac{ dy }{ dy } = -\frac{ x+2 }{ y-3 } \Rightarrow -\frac{ \left( -1 \right)+2 }{ \left( -3 \right)-3 } =-\frac{ 1 }{ -6 } =\frac{ 1 }{ 6 }\]

slope intercept form:

y-(-1)=1/6(x-(-3)) => y+1 = 1/6 (x+3)

Answer 14

ooops

y+3 = 1/6(x+1)

Answer 15

yeah, i see your point...

let me check dy/dx

Answer 16

ok thankyou

Answer 17

2(x+2)+2(y-3)y'=0

y' = -(x+2)/(y-3)

Answer 18

yep not sure of the issue. sorry i didn't pay closer attention at the start.

Answer 19

wait i forgot it does say circle do i need to write it in some form to match that

Answer 20

could it be it thinks the (x+1) is on the bottom? how you are typing it in? how do you do fractions in your program?

Answer 21

do they want slope-intercept form? y = mx+b

Answer 22

im not sure because the fact its suppose to take both forms

Answer 23

try y = x/6 - 17/6 or y = (x-17)/6

Answer 24

it took y=(x-17)/6 how did you get that

Answer 25

never mind i saw how you got it thank you