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Mathematics 19 Online
OpenStudy (anonymous):

Help with this

OpenStudy (anonymous):

The rational expression \[\frac{ x^{2} + 3x}{ 4x }\] is simplified to \[\frac{ x + 3 }{ 4 }\] . Explain why this new expression is not defined for all values of x.

OpenStudy (amistre64):

assume that we are looking at a map while trying to drive down the road. which is more important .... the bridge being out in front of you, or the map saying to cross the bridge?

OpenStudy (anonymous):

The bridge...

OpenStudy (amistre64):

yeah, the first expression models some real life issue. the simplified version is a map that can make things simpler but it doesnt really negate the real life issues does it

OpenStudy (amistre64):

x=0 is not a usable value in the real life issue. so regardless of how much we simplify it to make a map, x=0 is still not going to work for us

OpenStudy (anonymous):

So the answer would be... "the expression is not defined for all values of x because x can not equal to 4" ?

OpenStudy (amistre64):

... becuase x cannot be equal to 0. its simply not a part of the domain that we are simplifying with

OpenStudy (anonymous):

Ah, because x is not there, it's gone, right? So there is nothing to equal x to? So I would write "The new expression is not defined for all values of x because x is not part of the domain for the new expression. If there is no domain, it will remain not defined (undefined)."

OpenStudy (amistre64):

\[\frac{x^2+3x}{4x}=\frac{x}{x}~\frac{x+3}{4}\] now, x/x is defined for all x not equal to 0 since 0/0 is undefined

OpenStudy (amistre64):

that sounds fair to me

OpenStudy (anonymous):

So my response would be appropriate, yes?

OpenStudy (amistre64):

appropriate enough for me yes, but im not the one to grade it

OpenStudy (amistre64):

"... is not defined for all values of x because [0] is not part of the domain to start with ..."

OpenStudy (amistre64):

\[\frac xx~\frac{x+3}{4}=\frac{x+3}{4};~x\ne0\]

OpenStudy (anonymous):

Got it, thank you

OpenStudy (amistre64):

good luck :)

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