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Using quotient rule, how do i set up j(x)= (3x + cosx)/ f(x) to find j'(x)?
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\[(\frac{ u }{ v })\prime=\frac{ u \prime v-v \prime u }{ v^{2} }\]
where u and v are both functions of x
so what is u and v in your question?
j(x)= (3x + cosx) divided by f(x) I'm not sure if I have to separate them, like j(x)= (3x/f(x)) + (cosx/f(x)) and use both product and quotient rule
nonono, just plug the function in to the equation
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so your u is 3x + cos x and v is f(x)
is this right? j'(x)= f(x)(3-sinx) - (3x+cosx)f'(x) divided by [f(x)]^2
well I think this is final answer
ok thanks!!
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