Suppose F(x) = f(g(x)) and g(3) = 6, g '(3) = 4, f '(3) = 2, and f '(6) = 7. Find F '(3).
chain rule ....
yes, I understand that I have to do chain rule, I just don't understand how I'm supposed to get the answer.
define the chain rule for me
the chain rule is f(gx))' = f'(gx)) g'(x)
correct so lets just sub in the values they give you f'(g(3)) * g'(3)
ok, so that would be f'(6) * 4 = 7 * 4 = 28 is that right?
yep
Ok, thank you. I also have another question. With chain rule how would I take the derivative of function like so: W = uov ???
so, how would I find the derivative of W?
same way: just the names have changed uov = u(v) derive: u'(v) * v'
im assuming u o v is the usual notation for function composition
so "o" implies multiplication?
not conventionally no. 'o' is shorthand for 'composed of' fog means f, composed of g ... or simply f(g)
f*g means multiplication, or even fg
oh wait, uov means " u of v", is that right?
correct
ahhh, that makes things so much more clear. Thank you for the help!
youre welcome
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