Question

find the critical points of the function: f(x) = 6x3 + x2 + 6x

Answer 1

-18/8

Answer 2

Find f'(x). Set it to zero and solve for x.

Answer 3

it says that the answer you gave me is incorrect!

Answer 4

i tried that but i can't seem to get the critical points because the factoring doesn't work out

Answer 5

f(x) = 6x^3 + x^2 + 6x
f'(x) = ?

Answer 6

f'(x)=18x^2+2x+6

Answer 7

18x^2 + 2x + 6 = 0 or
9x^2 + x + 3 = 0
solve for x.

Answer 8

thats where i get stuck.
it doesn't factor out evenly

Answer 9

i don't know how to solve at that point

Answer 10

Use the quadratic formula.
If there are no real solutions there are no critical points.

Answer 11

ok ill try that! thanks so much