Question

Find the equation of the tangent line to the curve at the point . The equation of this tangent line can be written in the form where

Answer 1

Have you considered the 1st Derivative?

Answer 2

Find the equation of the tangent line to the curve y=4sin(x) at the point (Pi/6,2). The equation of this tangent line can be written in the form y=mx+b where m=? b=?

Answer 3

yes the first derivative is y=4cox(x)

Answer 4

m = y'(pi/6)

Answer 5

and b = -mx1 + y1

Answer 6

so would m just be 4cos(x)(pi/6)?

Answer 7

m = 4cos(pi/6)

Answer 8

ohhh okay

Answer 9

if we take point slope form:

y - y1 = m(x-x1)

and solve for y ...

y = mx - mx1 + y1

so y = mx + b is such that b=-mx1 + y1

Answer 10

so b would be .1862006358

Answer 11

maybe

-2sqrt(3) pi/6 + 2 , the wolf likes it

Answer 12

Thank you!

Answer 13

youre welcome