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Mathematics 9 Online
OpenStudy (anonymous):

Find dy/dx (e^x -e^-x)/(e^x+e^-x)

OpenStudy (nincompoop):

try solving

OpenStudy (anonymous):

I attempted logarithmic differentiation but did not know how to do it with all the subtracting

OpenStudy (nincompoop):

?

OpenStudy (nincompoop):

show me your work

OpenStudy (anonymous):

all I did was take the natural log of everything and subtracted

OpenStudy (nincompoop):

why not make it simpler by using quotient and chain rules?

OpenStudy (nincompoop):

natural log of everything?

OpenStudy (anonymous):

because isn't the natural log easier and what would be the u in the chain rule?

OpenStudy (nincompoop):

u = -x

OpenStudy (nincompoop):

isn't it neat?

OpenStudy (anonymous):

no I don't get it

OpenStudy (nincompoop):

set up as a quotient rule first

OpenStudy (anonymous):

and then to the u chain rule afterwards?

OpenStudy (nincompoop):

ye

OpenStudy (nincompoop):

are you doing it or what?

OpenStudy (anonymous):

yeah I doing it imam see how it comes out

OpenStudy (anonymous):

the top cancels out

OpenStudy (anonymous):

can I get some assitance

OpenStudy (anonymous):

does it help to know that this is \(\tanh(x)\) or do you not use hyperbolic functions?

OpenStudy (anonymous):

yeah I know what it is , is that needed

OpenStudy (anonymous):

or you can multiply top and bottom by \(e^x\) and get \[\frac{e^{2x}-1}{e^{2x}+1}\] if that makes it easier to use the quotient rule there is really no way around the quotient rule here

OpenStudy (anonymous):

okay so its just quotient rule? and messy work? could I take the natural log of everything

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