Question

consider the piecewise h(x) = -2/3(x+1) x<-1
-4x-4 -1≤ x≤ 0
x-8 1 11 years ago

Answer 1

@amistre64

Answer 2

In the first part, all x less than -1 are covered.
In the second part, all x from -1 to 0 with both -1 and 0 included. Combining with the above we have h(x) defined for all \(x \le 0\).
In the third part, x between 1 and 4 are covered.
So the domain of h(x) is:
\((-\infty, 0] \cup (1, 4)\)

Answer 3

We use a square bracket to include 0.
We use parenthesis (1, 4) to exclude the end points 1 and 4.