Question

fine b and c so that y=7x^2+bx+c has a vertex (4,-10)

Answer 1

using the line of symmetry, b = 4

and using the equation for the line of symmetry you get

\[4 = \frac{-b}{2 \times 7}\]

just solve for b

when you find b, put it into the equation.

then substitute the vertex, x = 4 and y = -10 into the equation to find c

hope it helps

Answer 2

well I got b = -56

so you have

\[-10 = 7 \times 4^2 - 56 \times 4 + c \]

that should help you find c