Question

give the configuration for a neutral atom of chlorine 3 point

Answer 1

Check the image I attached.
To get the configuration of an atom you start in the upper left corner and go to the right.
We start in the s block, first row. So the notation would be \(\large\sf1s\).
As we go to the right, you'll see another 1s, together this makes \(\large\sf1s^2\).
Then you start on the next row, in the second row of the s block. There are 2 elements in this row, that makes \(\large\sf2s^2\). As we go to the right we'll enter the second row of the p block. there are 6 elements here so that would be \(\large\sf2p^6\).
Chlorine is almost at the end of the 3rd row of the periodic table so we still have some blocks to go.
Next is the third row of the s block, again 2 elements, so \(\large\sf3s^2\). Then the 3p block. Chlorine is the 5th element in this row, so you would end with \(\large\sf3p^5\).

Put this all together and you'll get: \(\large\sf1s^22s^22p^63s^23p^5\)
Easy as that.