Question

A clock regulated by a seconds pendulum keeps correct time.During summer the length of the pendulum increases to 1.01m.How much will the clock gain or lose in one day?

Answer 1

@Mashy @nirmalnema @praxer

Answer 2

@cwrw238 help

Answer 3

@paki

Answer 4

can u help

Answer 5

can u tell whether the clock will lose or gain?

Answer 6

no idea

Answer 7

@ganeshie8

Answer 8

@amistre64 can you do some help here??

Answer 9

im thinking that a pendulum swing regulates itself and that the time frame essentially remains constant.

Answer 10

but im no expert :)

Answer 11

@Mashy help pls

Answer 12

The period of a simple pendulum is proportional to the square root of its length.
If you assume the period depends on the length and the acceleration due to gravity, then the result follows from dimensional analysis.
Knowing that period is proportional to square root of length, you should be able to work out the change in period for a 1percent change in length.

Answer 13

@Mashy help yaar

Answer 14

@ProfBrainstorm help

Answer 15

yes.. @ProfBrainstorm helped u enough..

the length went from 1 to 1.01
so the change = 1.01 - 1 = 0.01
so the percent increase = 0.01 * 100 = 1 %

also you know
\[T = 2 \pi \sqrt{ \frac{L}{g}}\]

Answer 16

so how much is the percentage increase in Time ?!

Answer 17

hey how u know L=1m

Answer 18

seconds pendulum = L = 1m

Answer 19

Just assume that the formula for the period of a simple pendulum is valid and plug in values for L and g to find T.
L=1.01m and g=9.81m/s^2
Then you can work out how many oscillations will have occured in one day.
Note that the period of an accurate seconds pendulum is actually 2 seconds, so it marks one second on each swing.