Question

Find the zeros of this function f (x)=x^2-25

Answer 1

You are just being asked to treat the function as a quadratic equation and solve for \[x\]

Answer 2

that is it

Answer 3

Actually thats just factoring, you have to find the values of \[x\] that 'zero' the function.

Answer 4

True, so, after you factor, get x alone for each x in the "()" i.e.
(x-5)(x+5)
x-5=0
x=5
I think you can get the other one

Answer 5

\[
x^2-25\qquad\text{is of the form}\\
a^2-b^2=(a+b)(a-b)\\\text{we can write}\\
x^2-25^2=(x)^2-(5)^2\\=(x+5)(x-5)
\\\text{to find roots, set it equal to } 0\\
(x+5)(x-5)=0\\\text{i.e., either}\\
x+5=0\qquad{\rm or}\qquad x-5=0\\
\implies \boxed{x=-5}\qquad{\rm or}\qquad \boxed{x=5}
\]

Answer 6

kapeesh?

Answer 7

At least let the man think, @electrokid .