solve the given differential equation by undetermined coefficients y'''-y''-4y'+4y=5-e^x+e^2x
You need to find the homogeneous solution. Have you done that yet?
yes and I got y=c1e^-2x+c2xe^-2x+c3e^x
Then I would make a guess at the particular solution being: \[y_p=Ae^{x}+Be^{2x}+C\]
how did you do it
I just looked at the right hand side of the differential equation.
And it is just really a guess. If it was a function like sin on the other side though I probably would chose the y_p to be like sin +cos
ok so what would the final solution be
if we have on t^4+t^3 on the side side i probably would have chose y_p as at^4+bt^3+ct^2+dt+e
also i forget to put constants in front that sin +cos thing
You have to plug in find the constants
how are you get these Im confused
what would the final answer be bc I have no idea
maybe pauls notes will help you
thank you for no help
you have to plug into find the constants
I wasn't done helping you
I just thought the notes would be beneficial to you
But I can go help someelse if you don't need my help.
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