MEDAL GIVEN!!!! find values X and Y that maximize or Minimize the objective function. 4x+ 3y >_ 30 x+3y>_ 21 x>_0, y>_0 Minimum for C = 5x + 8y
@MIA305DT @amistre64
@zkoqmosii
you are going to want to find where your critical region is and define its vertexes
what is that how do i find it
you are given a few lines to graph out, those lines will define the boundarys of some region in the plane
4x+ 3y >_ 30 x+3y>_ 21 x>_0, y>_0 <-- these are just the x and y axis
3,6
3.6 is one vertex, 0,0 is another, and you should have one on the y axis and the x aixs
y >_ 10 - 4x/3 for the 4x +3y >_ 30
y>_ 7- x/s for x+3y21
|dw:1412629321866:dw| hmm, since y> then the line this area seems like it would be unbounded
that point is 3,6 i know that
http://www.wolframalpha.com/input/?i=4x%2B+3y+%3E%3D+30%2C++x%2B3y%3E%3D+21 chk your information
otherwise, infinity, infinity is the maximum
okay thanks so how do i find the constraints in slope intercept form
solve for 'y'
didn't i do that already
4x+ 3y >_ 30 y >= -4/3 x + 10 x+3y>_ 21 y >= -1/3 x + 7
looks like you did yes
that the slope intercept?
yes
whats the objective function
teh objective function doesnt get ploted, it gets used when we find the corners of the 'bounded' area of the constraints
think of it like a surface that is floating above the area
k
each x,y in the area defines a height above it defined by the objective function|dw:1412629809588:dw|
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