write the equation of a parabola given that the vertex is 0,0 and the focus is 0,-1/2
@Kainui
@satellite73 @amistre64
Well start off by sketching a picture, the vertex is the "centre," and the focus is a fixed point on the interior of a parabola. Graphing will help you as it will tell you if it's vertical or horizontal, the formulas respectively. Vertical \[(x-h)^2=4p(y-k)\] Horizontal \[(y-k)^2=4p(x-h)\]
i think its vertical
vertex (h,k) and p = distance and direction from vertex to focus, distance and opposite direction from vertex to directrix.
i don't understand what P is
Cool, if you want further help from me you'll need to tell me more, "i think" is not useful.
ok... so if it was vertical, my equation would be (x-0)^2=4p(y-0)
Sure
so how do i determine what p is? is in -1/2 or 1?
p is the distance from v to d right?
which is the same distance from v to f
so its 1/2
then i get x^2=2y?
good, and our f is in the direction of the opening, so it opens down
-x^2 = 2y
why is x negative? because the graph is opening downwards?
yep
we have a focus under our vertex, we open towards the focus
so can the equation we got be simplified any more?
sure it can ... y = ___ x^2
what would i do if i wasnt given the vertex? like focus 4,0 and directrix -4
focus and directrix are extremes, with the vertex in the middle
so i would just find the middle of the 2?
so would it be -3,4?
yes, assuming the directrix is y=N maybe?
what is N?
the number of x or y that defines the directrix
a directrix of 4 is not enough information is it a line thru y=4 or thru x=4?
well, -4 but still
x=-4
|dw:1412636260222:dw| Drew this out just to show what goes on parabolas as such and what it really means, I hope that helps you visually.
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