bryan wanted to increase the concentration of a liter of hydrochloric acid from 30% to 35%. How much pure acid should he add
Is there a quantity it begins with?
nope
it says a liter of hydrochloric acid
Oh okay
how much pure acid should he add
idk the only way to get from 30 to 35 would be to add 5%
Start with a table
thats all i would think u would have to create a chart
yea i did a table but its not makin since
system of equations
let h = 1 liter, and n be the amount to add in h+n = (1+n) .30h + 1n = .35(1+n)
something similar to that
Starting solution Total Amount: 1 liter %HCL acid: 30 Total Amount of HCL acid: .3 liter Solution Added: x liter %HCL acid : 100 Total amount of HCL acid: 1x Resulting Solution: 1+x %HCL acid: 35 Total amount of HCL: .35(1+x) .35(1+x)= x+.3
seems we concur
Yeah @amistre64 then just solve for x and plug it into the table
x is the solution :)
its 5%
more like about .077 liters
not sure how you would add 5% pure acid as a solution
I think she's thinking a 30 % solution + 5% soultion would equal a 35% solution when Mixture problems work differently
yea lol
1liter at 30% + .077 liters at 100% = 1.077 liters at 35%
The quantity of the starting solution has to be acknowledged which is in this case a liter
The chemist is adding pure HCL which is .77 liters at 100% to make a 30 percent solution equal 35 percent
http://www.wolframalpha.com/input/?i=.30+%2B+n+%3D+.35%281%2Bn%29 .077 is what im getting, so im assuming a typo
lol theirs no typo
Yeah lol I didn't solve it I was just parroting your answer. @cali16 Lol he was talking to me.
Yeah it's .077
good luck yall ;)
But do you get it @cali16
yes now i do thx!!!
No problem.
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