Question

I really need help starting this

Answer 1

\[\sqrt[3]{2h^4} \times \sqrt[3]{4h ^{16}}\]

Answer 2

you could start with
\[\sqrt[3]{8h^{20}}\]

Answer 3

might help since \(\sqrt[3]{8}=2\)

Answer 4

I thought they were suppose to have matching exponents in order to combine them?

Answer 5

not so long as the bases are the same
you are not done yet though, you need to write it in simplest radical form

Answer 6

so yeah I got 2 to the cube root of h^20. h^20 would simplify more wouldn't it?

Answer 7

yes
3 goes in to 20 6 times, with a remainder of 2
\(h^6\) comes outside the radical, \(h^2\) stays inside

Answer 8

So when you did that you just did 20/3 basically right?

Answer 9

yeah sort of

Answer 10

i guess you could say \(\frac{20}{3}=6\tfrac{2}{3}\)

Answer 11

ohhhhhhhh! ohmygod thanks so much for your help! didn't know it was that easy XD

Answer 12

yw
and yes, it is that easy!