I really need help starting this
\[\sqrt[3]{2h^4} \times \sqrt[3]{4h ^{16}}\]
you could start with \[\sqrt[3]{8h^{20}}\]
might help since \(\sqrt[3]{8}=2\)
I thought they were suppose to have matching exponents in order to combine them?
not so long as the bases are the same you are not done yet though, you need to write it in simplest radical form
so yeah I got 2 to the cube root of h^20. h^20 would simplify more wouldn't it?
yes 3 goes in to 20 6 times, with a remainder of 2 \(h^6\) comes outside the radical, \(h^2\) stays inside
So when you did that you just did 20/3 basically right?
yeah sort of
i guess you could say \(\frac{20}{3}=6\tfrac{2}{3}\)
ohhhhhhhh! ohmygod thanks so much for your help! didn't know it was that easy XD
yw and yes, it is that easy!
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