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\[\sqrt{x-4}-\sqrt[4]{x-4}=6\] why is the solution 85
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please help and list each step, I am so confused
u have \[\large \sqrt{x-4}-\sqrt[4]{x-4}=6 \] which can be rewritten as \[\large \sqrt{x-4}-\sqrt{\sqrt{x-4}}=6 \]
now let \(Y=\sqrt{x-4}\) so u have \[\large Y-\sqrt{Y}=6 \] or \[\large Y-6=\sqrt{Y} \] square both sides \[\large Y^2-12Y+36=Y \] or \[\large Y^2-13Y+36=0 \]
I still don't understand?
this can be factored into (Y-4)(Y-9)=0
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if Y=4 then \(\sqrt{x-4}=4\) gives you x=20
if Y=9 then \(\sqrt{x-4}=9\) gives you x=85
which part don't u understand? (sorry i'am having some problems posting things.)
oh i understand now!! I didn't realize the factoring
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