Question

Please help...MY kid needs help, I don't understand this

3 to the negative 1th power x 7 to 7th power x (3 to the 4th power)3rd power divided by 21 to the 9th power =

Answer 1

Just so we're clear on the problem, do you mean to give us a variable when you write "x" or is that to indicate multiplication?

Answer 2

no is multiply

Answer 3

x is (times / multiply) sorry for the confusion

Answer 4

Then it should look like this, yes?

\[\frac{ (3^{-1})(7^{7})((3^{4})^{3}) }{ (21^{9}) }\]

Answer 5

no ) on the last 3

Answer 6

Can you use the equation button below to show exactly how it looks on the page? Because \[(3^{4})^{3}\] is very different from \[3^{(4^{3})}\]
In either case, the first thing that might help is to realize that \[3^{-1}\] is the same as 1/3, so you can just get rid of the negative exponent and move that three into the denominator of the fraction. Then, it's just a matter of tending to all of the multiplications and divisions to come to a final answer.