Question

A car goes around a curve on a road that is banked at an angle of 34.5∘ . Even though the road is slick, the car will stay on the road without any friction between its tires and the road when its speed is 23.0m/s .
What is the radius of the curve?

Answer 1

whats the answer lol

Answer 2

@Pompeii00

Answer 3

running short on time.. this online hw due at 12

Answer 4

its wrong. thanks thoug

Answer 5

still wong

Answer 6

**wrong

Answer 7

@Pompeii00

Answer 8

I must be tired, i just made some dumb mistakes. I apologize since you were trying to get this done in a timely manner.

So let me just show a solution. This should be correct.

From this, we see that Fn cos(a) = mg
Fn = mg/cos(a)

Now, we are only concerned with horizontal forces, since that provides the centripetal force.

Fn sin(a) = mg/cos(a) * sin(a) = mg tan(a)

Centripetal force is: Fc = mv^2 / r = mg tan(a)
v^2 / r = g tan(a)
r = v^2 / g tan(a) = (23)^2 / (9.8)(tan(34.5))

r = 78.5 m