Question

4+2i/3-i

Answer 1

\[\frac{4+2i}{3-i}\] and you need to write in standard form as \(a+bi\) right?

Answer 2

Yes.

Answer 3

u know rationalization??

Answer 4

Uh..no.

Answer 5

ok than multiply and divide by 3+i

Answer 6

in this we have to remove i from denominator

Answer 7

What is i?

Answer 8

in our Q it is given

Answer 9

it represent imaginary part of complex number

Answer 10

It's multiple choice.

Answer 11

first multiply with 3+i and divide by it also

Answer 12

then guess C , it is usually C

Answer 13

loll

Answer 14

a) 7 + 5i/ 5
b) 5+5i/ 4
c) 7+5i/4
d) 1 + i

Answer 15

I haven't been having much luck with C lately.

Answer 16

well then lets do it all

Answer 17

Huh?

Answer 18

\[\frac{4+2i}{3-i}\times \frac{3+i}{3+i}\] is a start
then since \((a+bi)(a-bi)=a^2+b^2\) a real number, your denominator will be \(9^2+1^2=10\) and you have
\[\frac{(4+2i)(3+i)}{10}\]

Answer 19

all that is left is to multiply out in the top to see what you get

Answer 20

you know how to multiply \((4+2i)(3+i)\) ?

Answer 21

10 + 10i?