Question

I got this question wrong on the exam and I know the right answer now but I do not understand how to get to it still.
When the following equation is balanced, the coefficient of O2 is ______.

Answer 1

C2H4O2 (g) + O2(g) ----> CO2 (g) + H20 (g)

Answer 2

what is the part that you dont understand?

C2H4O2 (g) + 2O2(g) ---->2 CO2 (g) + 2 H20 (g)

Answer 3

the exam says it's supposed to be 5 o2

Answer 4

because i had 2 O2....and that was wrong.

Answer 5

first you balance the C, two in each side
then the H, with the waters, 4 in each side
last the O , in the products you have 2x2 from the CO2 +2 from the water = 6 O, in the reactants you have 2 in the C2H4O2 you have to balance with 4 more but O is diatomic so you add a 2

Answer 6

...hmm so i had it right and the professor has it wrong then?

Answer 7

did he put 5 in front of the O2?

Answer 8

yea

Answer 9

...at least you typed wrong some of the other compounds in the formula, I will not agree with a 5, It is not going to balance the equation.

Answer 10

okay, i'll ask my tutor.

Answer 11

5C2H4O2(g) + 5O2(g) = 10CO2(g) + H20(g) this is not balanced the H2O
5C2H4O2(g) + 10O2(g) = 10CO2(g) + 10H20(g)