please please help me. ;-; IM STUUUCCCKKK bleehh
whats your problem?
Simplify the following expression. \[(4^6)^2\] And it would be awesome if you could explain how top do this! c:
Ok, so according to PEMDAS, you do parentheses first, right?
So, do I figure out whats in the parenthesis and then add the exponent that is not in the parenthesis to the figured out one that is in the parenthesis? I hope thats understandable...
\[\large (a^m)^n = a^{m~*~n} = a^{mn}\]
@aum is right
you will multiply the exponent numbers. What product does that give you?
\[4^12\] The 2 is part of the exponent
\[\large (4^6)^2 = 4^{6~*~2} = 4^{12}\]
yes, now what is 4 to the 12 power?
could you guys give a medal to each other? Because I can only medal one person at a time. :/
In Latex enclose the exponent in curly braces 4^{1/2} will display \(\large 4^{1/2}\).
yea, I'll give one to @aum
@k_lynn Thats all I needed to figure out. c:
Great! Hoped that helped.
Could you help me with a few more?
sure
https://media.studyisland.com/cgi-bin/mimetex.cgi?2^ {2}%20\%20\div%20\%202^{6}
\[ 4^{1/2} = ? \\ 4 = 2^2 \\ 4^{1/2} = (2^2)^{1/2} = 2^{2 ~*~1/2} = 2^1 = 2 \]
Sorry, it didnt go on here right cx
\[\large \frac{2^2}{2^6} = 2^{2-6} = 2^{-4} = \frac{1}{2^4} = \frac{1}{16} \]
Oh, okay. I didn't realize I would do that using fractions. :)
Ok, so what is 2 to the 2 power?
4
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