Question

consider h(x)=-x^2+8x+15. Identify its vertex and y-intercept.

Answer 1

the vertex is (-4, -1) and the Y-intercept is (0,15) .

Answer 2

For the parabola y = ax^2 + bx + c, the x-coordinate of the vertex is given by -b/(2a). Find the x-coordinate of the vertex using this formula. Then put the x-value in the equation and calculate the y-value.

Answer 3

if you need an explanation just ask

Answer 4

Please don't give direct answers. Help the student learn.

Answer 5

how do i calculate the y-intercept?

Answer 6

y-intercept is when x = 0. Put x = 0 in the equation and calculate y.

Answer 7

oh, alright thanks so much.

Answer 8

You are welcome.

Answer 9

The vertex is different from the answer given above.

Answer 10

okay

Answer 11

how did i find the minimum or maximum of g(x)=x^2+9x-36 ?

Answer 12

x^2+9x-36 is a parabola.
Since the leading coefficient is positive, this is a parabola that opens upward.
Therefore, it has a minimum and the minimum occurs at the vertex.
Use the same method described above.
The x-coordinate of the vertex is at -b/(2a). Put that x value in x^2+9x-36 and find the y value and that will be the minimum.