Question

aaa

Answer 1

i will answer u if u can help me beautiful

Answer 2

Na help me first

Answer 3

ok cool babe

Answer 4

http://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=0CCAQFjAA&url=http%3A%2F%2Fwww.algebra.com%2Falgebra%2Fhomework%2Fword%2Ftravel%2FTravel_Word_Problems.faq%3Fhide_answers%3D1%26beginning%3D5400&ei=_2E0VKu2BNKtyATP34KQBg&usg=AFQjCNGrVAMNBFfHSRXj20WNhjTLWlqRSA&bvm=bv.76943099,d.aWw

Answer 5

there is a web site

Answer 6

did u find what u are looking for

Answer 7

Let T be the time, in hours, spent ying at 600 mph. In the mid-
dle of the ight, after the rst half hour and before the last half hour, the plane
travels a distance of 600
T
miles.
In the rst half hour, the plane travels 300(
1
2
) = 150 miles.
In the last half hour, the plane travels 300(
1
2
) = 150 miles.
So the total distance traveled is 2100 = 150 + 600
T
+ 150 = 300 + 600
T
.
Solving this equation for T, we get
2100

Answer 8

total distance =d1(first hour) +d2 (middle)+d3(last hour)

speed=distance/time,distance =speed *time


\(\large\tt \color{black}{6300=d_1+d_2+d_3}\)

\(\large\tt \color{black}{6300=s_1\times t_1+s_2\times t_2+s_3\times t_3}\)

\(\large\tt \color{black}{6300=300\times \dfrac{1}{2}+600\times t_2+300\times \dfrac{1}{2}}\)

\(\large\tt \color{black}{6300=150+600\times t_2+150}\)

\(\large\tt \color{black}{6000=600\times t_2}\)

\(\large\tt \color{black}{ t_2=10}\)

\(\large\tt \color{black}{total~time=t_1+t_2+t_3}\)

\(\large\tt \color{black}{t=\dfrac{1}{2}+10+\dfrac{1}{2}}\)


\(\large\tt \color{black}{t=11~~hrs}\)

Answer 9

wait but I got 11.5..? @mathmath333

Answer 10

guessed