Question

I REALLY NEED HELP PLEASE !
Thanks

Answer 1

@dumbcow @myininaya @amistre64 @superhelp101

Answer 2

have you graphed the constraints?

Answer 3

No i dont really understand what to do

Answer 4

ok lets me give you a step by step

step 1:
graph the constraints. there are 3 inequalities which represent 3 lines, also x,y > 0
put each equation into y < mx +b form, where m is slope, b is y-intercept

step 2:
find the region bounded by the lines on graph
find the points of intersection which can be found by setting 2 equations equal to each other

step 3:
evaluate objective function using the intersection points
- these are all the sharp points around the bounded region
plug in each (x,y) point and see which one gives the greatest value

Answer 5

So the equations would be y less than or equal to -x+80
2y less than or equal to -3x +220
3y less than or equal to-2x +210
y greater than or equal to -x+0

Answer 6

yes except the last one .... its not x+y >0 , its saying x>0 and y>0

Answer 7

Okay so now i would graph them

Answer 8

I got (30,0)

Answer 9

as the intersection point

Answer 10

sorry here is better graph
http://www.wolframalpha.com/input/?i=plot+%28-x%2B80%2C+-3x%2F2+%2B+110%2C+-2x%2F3+%2B+70%29+for+0%3Cx%3C80

Answer 11

In the graph you just send me there is not a point where all the lines meet

Answer 12

that is correct, they do not .... mine is off because i did it by hand without a real scale

Answer 13

OKay so what does that mean

Answer 14

the points of intersection define the optimal point around the bounded region

Answer 15

Sorry im just very confused about this

Answer 16

okay so the lines dont have to touch

Answer 17

this is region defined by the given constraints, so only the x,y points within this region can be used in the objective function
P = 5x +6y

the four intersection points i made around the edge will give the extreme values
find those points and plug them in
one of them will be the max value for P = 5x+6y