Question

degree of 2 zeros: 1-2i

Answer 1

much easier than it looks
there is an easy way, and a really really easy way
lets do the easy way first

Answer 2

okay

Answer 3

work backwards, like solving a quadratic equation backwards
\[x=1-2i\] subtract \(1\)
\[x-1=2i\] square both sides (carefully)
\[(x-1)^2=(2i)^2\\
x^2-2x+1=-4\] then add \(4\) and finish with
\[x^2-2x+5\]

Answer 4

want to try the really really easy way?

Answer 5

sure !

Answer 6

it is really really easy but it requires memorizing something
if the zero of a quadratic is \(a+bi\) then the quadratic is
\[x^2-2ax+(a^2+b^2)\]
you had \(1+2i\) so the quadratic is
\[x^2-2\times 1x+(1^2+2^2)=x^2-2x+5\]

Answer 7

what about when it tell you .. degree 3 zeros -1 with a multiplicity of 3 ?

Answer 8

is -1 a and 3 b ?