Question

Calculus question: Use Part 1 of FTC to find the derivative of the function

Answer 1

\[g(x)=\int\limits_{4}^{x}e ^{4t ^{2}-4} dt\] gprime(x)=

Answer 2

Just replace the x with the variable t

Answer 3

It's that easy

Answer 4

wow...i feel dumb >_<

Answer 5

\[\huge g'(x) = e^{4x^2-4}\]

Answer 6

Thanks!

Answer 7

Np :)

Answer 8

The fundamental theorem of calc part 1 states this,

If f is continuous on [a,b] then \[g(x) = \int\limits_{a}^{x} f(t) dt~~~~a \le x \le b\] is continuous on [a,b] differentiable on (a,b) and \[g'(x) = f(x)\]

Answer 9

Basically saying plug in x for t haha.

Answer 10

Or what ever the variable is :P