calculus Q: Consider the function f(x)=x2+9x+2 and the point A(16,2).

f′(x)= 2x+9
slope= (x^2+9x)/(x-16)

Using your answers from the two previous questions, find the slope(s) of the line(s) through point A that is (are) tangent to f(x). If there is more than one line you can separate your answers with a comma (ex. 5,2 ).
slope(s)=

Question

calculus Q: Consider the function f(x)=x2+9x+2 and the point A(16,2).

f′(x)= 2x+9
slope= (x^2+9x)/(x-16)


Using your answers from the two previous questions, find the slope(s) of the line(s) through point A that is (are) tangent to f(x). If there is more than one line you can separate your answers with a comma (ex. 5,2 ). 
slope(s)=

anonymous · Answer

@iambatman

anonymous · Answer

I've solved part 1 and part 2, really stuck on part 3.

anonymous · Answer

@aum

anonymous · Answer

The hint for this question was: 
Hint: To find the slope function, use ΔyΔx, noting that in this case one of the y values will be a function. Set the derivative function equal to the slope function. Solve for x and evaluate the derivative at the values that you find.

anonymous · Answer

I did that. and I got (x+36) (x-4) ....which came out to be x=-36 and x=4...I substituted those values into 2x+9 and got 17 and -63. this was incorrect though.

anonymous · Answer

x^2-32x-144 was the quadratic equation and that's how I got (x+36)(x-4)