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Mathematics 16 Online
OpenStudy (anonymous):

Which expression is a sixth root of -1+ i sqrt 3?

OpenStudy (anonymous):

\[-1 + i \sqrt{3}\]

OpenStudy (anonymous):

Can anyone help me do this??

OpenStudy (tkhunny):

Do you have DeMoivre? That is what you need.

OpenStudy (anonymous):

My lesson mentions it, but they don't exactly give me a formula or anything.

OpenStudy (tkhunny):

Find the angle and magnitude represented by the number given.

OpenStudy (anonymous):

I'm totally lost. Sorry. Can you explain to me how to do that?

OpenStudy (tkhunny):

Can you rephrase the number in Polar Coordinates. You must be able to do this or you cannot solve the problem using DeMoivre - which is, by far, the easiest way to go about it. Map it on Cartesian coordinates and find the equivalent point in Polar Coordinates.

OpenStudy (anonymous):

Ohh okay. Let me do that.

OpenStudy (anonymous):

I keep getting an odd number. I don't think it's correct.

OpenStudy (tkhunny):

Show it and how you got it.

OpenStudy (anonymous):

My schooling program just gave me answer choices as a hint:

OpenStudy (tkhunny):

Okay, how do we get the right one? You MUST be able to write the number in Polar Form. It can look like those answer choices.

OpenStudy (anonymous):

I'm honestly not too sure how to do that.

OpenStudy (anonymous):

Wait. Is it the z= a+bi?

OpenStudy (tkhunny):

|dw:1412788533959:dw| Make sense?

OpenStudy (anonymous):

Yes. Is the polar form x= 2(cos(\[2\pi/3) + isin (2\pi/3))\]?

OpenStudy (anonymous):

\[z= 2(\cos(2\pi/3) + isin (2\pi/3))\]

OpenStudy (tkhunny):

Super!! Just one thing, though. Looking at the answers, we should write it in degrees. \(x = 2\left(\cos(120º)+i\sin(120º)\right)\) There is no compelling reason for this. It's just how the answers will want it to appear. Okay, how do we find ALL SIX of the sixth roots of this thing?

OpenStudy (anonymous):

Do we take the 6th root of everything?

OpenStudy (tkhunny):

This is where DeMoivre comes in. The FIRST one is \(2^{1/6}\left(\cos(120º/6)+i\sin(120º/6)\right)\) or \(2^{1/6}\left(\cos(20º)+i\sin(20º)\right)\) If that's all you need to solve the problem, then we are done. If you don't find this one in the list, you will need the other five.

OpenStudy (anonymous):

Does this mean it would be \[\sqrt[6]{2}(\cos(20) + isin(20))\] ?

OpenStudy (tkhunny):

And there are five more. \(360º/6 = 60º\). Every 60º there is another one. 20º, 80º, 140º, 200º, 260º, 340º

OpenStudy (anonymous):

But how do I know which on is the sixth?

OpenStudy (anonymous):

Nevermind. I understand now. Than you so much :)

OpenStudy (tkhunny):

The are ALL the sixth roots of the value where we started. All of them! There are 6.

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