gloria had rectangle garden plot last year with an area of 60 feet square.This year glorias garden plot is one foot wider and three feet shorter than last years garden,but it has the same area.What were the dimensions of the garden last year?
@phi
@e.mccormick
@ganeshie8
@mary.rojas
@mathmath333
I think it is something like...... 60= (1+w)*(L-3) Where w is the width and L is the length You can use any letters to represent them in the equation. Now solve for w and then solve for L. And that will be the answer...I think Good luck and hope it helps
thank you my teacher gave me this equation he said the A=l times w so he said 30*2
hmmmm...but you may have to keep in mind that this is for the new garden...so you would have to keep in mind that teh original was w*L=60
thanks for the help
Well, that is good that your teacher helped you! :)
h:)
@Bush993
@Bush993
@Bush993
@superhelp101
@superhelp101
i could explain this to you but i'll take a while this website is awesome thou http://www.algebra.com/algebra/homework/word/geometry/Geometry_Word_Problems.faq.question.438542.html
thank you @superhelp101
@tester97
@ganeshie8
as mary.rojas has started already, solve : WL = 60 (W+1)(L-3)=60
60=W*L W=60/L .....1 60=(W+1)(L-3) 60=(60/L+1)(L-3) 60=60-180/L+L-3 60=57-180/L+L 60L=57L-180+L^2 3L-L^2=180 L^2-3L-180=0 (L+12)(L-15)=0 L=-12 L=15 then L=15 W=60/15 then W=4 in the last year W+1=5 L-3=12
@ganeshie8 i dont understand how to do this
can you plz help me through the equation above @ganeshie8
WL = 60 (W+1)(L-3)=60
from the first equation, L = 60/W plug this in second equation, you get : (W+1)(60/W - 3) = 60
expand that, you will get a quadratic.. solve it
um -5 and 4 is w i
@ganeshie8
what is a quadratic @ganeshie8
thats right! pick W = 4 because the lengths cannot be negative http://www.wolframalpha.com/input/?i=solve+W*L+%3D+60%2C+%28W%2B1%29%28L-3%29%3D60%2CW%3E0
whats the last year and this year length though
@ganeshie8
@Isaiah.Feynman can you walk me through this problem
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