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what is the slope of x^2/16+y^2/36=1 at point (x,y)?
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It seems you are asked to find the "slope" formula aka the derivative of y w.r.t x
so start by differentiating both sides
I could find the slope with a point, but the point (x,y) is throwing my off.
Do you know how to find the derivative?
of x^2 and y^2 and a constant w.r.t. x?
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I'm asking if you know how to evaluate the following: \[\frac{d(x^2)}{dx} =? \\ \frac{d(y^2)}{dx} =? \\ \frac{d(1)}{dx}=?\]
welcome to OS @teach14 :)
just follow what he helped u and tell him/her ..so that he can help u further
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