Question

NaOH + HCl = NaCl + H2O
if 8.00mL of HCl requires 7.52mL of 0.10M NaOH to consume the HCl (or titrate to completion), what is the concentration of HCl?

Answer 1

Start by changing 7.52ml to L (0.00752) then multiply it by 0.1 to get your moles of NaOH

Answer 2

Balance your equation. Then proceed to change moles NaOH to moles HCl. Which by the equation is 1:1 so moles NAOH = moles HCl. You have 7.52x10-4 moles HCl.

Answer 3

Then with the volume of HCl, 8ml, change it to L (Liters) which is 0.008 and do Moles/Volume.

Answer 4

So finally 7.52x10-4 / 0.008 = 0.094M!

Answer 5

^well done. As a shortcut you could use: \(M_1V_1=M_2V_2\)

\((0.10M )(7.52mL)=M_2(8.00mL)\rightarrow M_2=\dfrac{(0.10M )(7.52\cancel{mL})}{8.00\cancel{mL}}=0.094~M\)