Mathematics
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OpenStudy (anonymous):
f(x) = 3 x^{6} \sqrt{x} + \frac{-3} {x^{2} \sqrt{x} }.
how do you find the derivative
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geerky42 (geerky42):
\[f(x) = 3 x^{6} \sqrt{x} + \frac{-3} {x^{2} \sqrt{x} }\]?
geerky42 (geerky42):
Just apply sum and power rule.
OpenStudy (anonymous):
yes but i dont know how to do this
OpenStudy (anonymous):
okay so use the product rule for the first half and then use the quotient rule for the second half
geerky42 (geerky42):
\(x^n\sqrt x = x^{n+1/2}\)
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geerky42 (geerky42):
Nah, we only need power rule
geerky42 (geerky42):
So... \[\begin{align}
3 x^{6} \sqrt{x} + \frac{-3} {x^{2} \sqrt{x} } &= 3 x^{13/2} - \frac{3} {x^{5/2}}\\~\\&= 3 x^{13/2} - 3x^{-5/2}
\end{align}\]
Now apply power rule: \(\dfrac{d}{dx}x^n = nx^{n-1}\)
OpenStudy (anonymous):
what is n
geerky42 (geerky42):
Any number
geerky42 (geerky42):
While taking derivative of x, you just multiply it by its exponent, then subtract its exponent by 1.
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OpenStudy (anonymous):
yes but if i put that as my answer it comes out wrong
geerky42 (geerky42):
You don't put \(d/dx~x^n = nx^{n-1}\) as answer... It's just power rule you need to apply.
OpenStudy (anonymous):
so how can i find the answer
geerky42 (geerky42):
Let's do a few easy questions. What is derivative of \(x^2\)?
OpenStudy (anonymous):
2x
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geerky42 (geerky42):
Yes, what about \(x^3\)?
OpenStudy (anonymous):
i know how to apply the power rule
geerky42 (geerky42):
ok, what are you struggle with?
OpenStudy (anonymous):
3x^2
OpenStudy (anonymous):
to find the answer
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geerky42 (geerky42):
Well, just take derivative, then simplify
geerky42 (geerky42):
Remember sum rule; basically you just derivative each term individually.
OpenStudy (anonymous):
so its 13/3 times 3
geerky42 (geerky42):
13/2 times 3. Times x with what exponent?
OpenStudy (anonymous):
i dont follow
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geerky42 (geerky42):
\(3*\dfrac{13}{2}x^?\)
OpenStudy (anonymous):
dont you subtract 13/2-1
geerky42 (geerky42):
Yeah, so \(3*\dfrac{13}{2}x^{11/2}\)
Now do next term. can you find derivative of that term?
OpenStudy (anonymous):
7.5/x^7/2?
geerky42 (geerky42):
Yeah, so you have \(\dfrac{d}{dx}f(x) = \boxed{\dfrac{39}{2}x^{11/2} + \dfrac{15}{2x^{7/2}}}\)
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OpenStudy (anonymous):
how did you get 15
geerky42 (geerky42):
\(7.5 = \dfrac{15}{2}\)
OpenStudy (anonymous):
Thank you so much I appreciate it
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
how did you get x^5/2 in the begininng
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OpenStudy (anonymous):
and 3x^13/2
geerky42 (geerky42):
\(x^2\sqrt x = x^{2+\frac{1}{2}}=x^{\frac{4}{2}+\frac{1}{2}} = x^{5/2}\)
Same for \(x^{13/2}\)
OpenStudy (anonymous):
Thank you I get it