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A particle moves along a straight line with equation of motion s = t^{5} - 4 t^{4} Find the value of t (other than 0 ) at which the acceleration is equal to zero.
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To find the equation of acceleration, you need to take derivative of equation of motion twice.
Can you find acceleration? @manhani
20t^3-48t^2
Yeah, looks good. Now set it equals to 0. Can you solve for t?
do i factor it
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Yes. factor \(t^2\) out
tsq(20t-48)
you can take out a 4
yeah was about to say that lol
so factor out \(4t^2\)
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4t2(5t-12)
So you have \(4t^2(5t-12)=0\) Either \(4t^2=0\) (t is 0 so we ignore it) or \(5t-12=0\) So solve for t in \(5t-12=0\)
12/5
thank you
No problem
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