Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (kainui):

What are the possible values of a and b?

OpenStudy (kainui):

\[\LARGE (x+1)+(x+a)^b = (x+1)(x+b)^a\]

OpenStudy (gorv):

x+1 will cancelled from both side

OpenStudy (gorv):

\[(x+a)^b=(x+b)^a\]

OpenStudy (gorv):

both will equal if and only if

OpenStudy (gorv):

1 their base are equal that is x+a=x+b 2. their power are equal that is a=b

OpenStudy (kainui):

How will they "cancel"?

OpenStudy (gorv):

we will divide bot side by x+1

OpenStudy (kainui):

Yeah, except it's added on the left side not multiplied, that won't work.

OpenStudy (gorv):

but you multiplied in your Q check that

OpenStudy (kainui):

Yeah I'm checking, you're wrong.

OpenStudy (gorv):

oohh sorry you said abt left side

OpenStudy (kainui):

Some things I'm noticing, if we do divide both sides by x+a we get \[\LARGE 1 + (x+a)^{b-1}=(x+b)^a\] And there is this random example I found by trying stuff out. \[\LARGE (x+1)+(x+1)^2=(x+1)(x+2)\]

OpenStudy (gorv):

hmmm..try log

OpenStudy (kainui):

I made this problem up, so if someone wants to change something about it maybe we can figure out something interesting of something more general.

OpenStudy (kainui):

How about this instead, what numbers can we choose for a,b,c, and d: \[\LARGE (x+a)^b+(x+c)^d=(x+b)^a(x+d)^c\] Obviously the example I chose we know a=a, b=1, c=2, d=1 is a working answer.

OpenStudy (gorv):

formula i have no idea ..but either go by random or solve

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!