Question

If x-(1/x)=1 then (x^4-(1/x^2))/3x^2+5x-3 is

Answer 1

3x^2+5x-3 can be written as divided it by x so 3x+5-3/x
3(x-1/x)+5 so it is 8

Answer 2

then numerator (x^2-1/x)^2

Answer 3

i feel numerator i am not getting

Answer 4

(x^2-1/x)(x^2+1/x)so we get x^4-1/x^2

Answer 5

yeah it is

Answer 6

how to get numerator to x-1/x format

Answer 7

(x^4-1)/x^2=

Answer 8

u know x^4-1=(x^2-1)*(x^2+1)

Answer 9

and it is divided by x^2 in Q

Answer 10

(x^2)^2-(1/x)^2 so

Answer 11

\[\frac{ x^2-1 }{ x }*\frac{ x^2+1}{ x }\]

Answer 12

x^2=x*x take one x below each factor

Answer 13

latex not working

Answer 14

\[\frac{ x^2-1 }{ x }=\frac{ x^2 }{ x }-\frac{ 1 }{ x }\]

Answer 15

x-1/x

Answer 16

1*1

Answer 17

1/8

Answer 18

other part
\[\frac{ x^2 +1}{ x}=\frac{ x^2 }{ x }+\frac{ 1 }{ x }\]

Answer 19

x+1/x

Answer 20

yes i was thinking about that only

Answer 21

numerator
\[(x-\frac{ 1 }{ x})*(x+\frac{ 1 }{ x })\]

Answer 22

x=1+1/x so x+1/x=x

Answer 23

(x-1/x)^2=1

Answer 24

so it is 1/8

Answer 25

wait

Answer 26

something went wrong over here

Answer 27

x^2+1/x^2-2=1
x^2+1/x^2=1+2=3

Answer 28

yes

Answer 29

but (x+1/x)^2=x^2+1/x^2+1

Answer 30

but we know x^2+1/x^2 =3 we calculated just above

Answer 31

there also 2 insead of 1

Answer 32

(x+1/x)^2=3+2=5

Answer 33

that will be 2 ..typin mistake

Answer 34

x+1/x=sqrt5

Answer 35

1*sqrt5/8 is ans

Answer 36

no

Answer 37

what??

Answer 38

yes see (x^2-1/x)*(x^2+1/x)

Answer 39

that will be x^2 not x

Answer 40

(x^2)^2-(1/x)^2

Answer 41

how

Answer 42

\[\frac{ x^4-1 }{ x^2}=\frac{ x^4}{ x^2 }-\frac{ 1 }{ x^2 }\]

Answer 43

got me ??

Answer 44

\[\frac{ x^4-1 }{ x^2}=\frac{ x^4}{ x^2 }-\frac{ 1 }{ x^2 }\].i can only see this

Answer 45

ohh i cant able to see do u calculation without using latex

Answer 46

\[\frac{ x^4 }{ x^2 }= x^2\]

Answer 47

\[x^2-\frac{ 1 }{ x^2 }=(x-\frac{ 1 }{ x })*(x+\frac{ 1 }{ x })\]

Answer 48

if we divide it by x^2 then 1/x becomes1/x^3

Answer 49

x^4-1/x^2 yes

Answer 50

how ????

Answer 51

(x^4-1)/x^2

Answer 52

here x^2 divide whole term

Answer 53

see the question above

Answer 54

(x^4-1/X^2)????

Answer 55

(x^4-(1/x^2))/3x^2+5x-3

Answer 56

ohhhhhhh

Answer 57

sorryyy i think x^2 DIVID E WHOLE

Answer 58

ohh very sorry u understood like that ah

Answer 59

thn u did right

Answer 60

above

Answer 61

then proceed to get x-1/x

Answer 62

x-1/x=1
1/x=x-1

Answer 63

put this in that equation

Answer 64

(x^2-(1/x))*(x^2+(1/x)) so
(x^2)^2-(1/x)^2

Answer 65

x-1/x=1
x-1=1/x
put x-1 in place of 1/x

Answer 66

(x^2-1/x)(x^2+1/x)

Answer 67

(x^2-(x-1))(x^2+x-1)

Answer 68

then we get x^4-x^2+1

Answer 69

(x^2-x+1)(x^2+x+1)
now
x^2-x+1=x(x-1+1/x)

Answer 70

ohh yes

Answer 71

x^4-x^2+2x-1
divide by x^2
we get x^2-1+2/x-1/x

Answer 72

sorry x^2-1+2/x-1/x^2

Answer 73

x-1=x

Answer 74

wrong now also x-(1/x)

Answer 75

x-(1/x)=1

Answer 76

1/x=x+1 okay

Answer 77

x-1

Answer 78

(x-1)/x=1
so x-1=x right

Answer 79

1/x=x+1

Answer 80

x-(1/x)=1

Answer 81

can we call ganeshie

Answer 82

yes

Answer 83

sure u can if u want :)

Answer 84

x^2-1/x^2-1-2/x

Answer 85

frm where u get this ??

Answer 86

x^4-x^2-2x-1
divide by x^2

Answer 87

(x^2-x-1)(x^2+x+1)

Answer 88

yeah

Answer 89

we didnt get by nowwht we want

Answer 90

(x^2-x-1)(x^2+x+1)
x^4-x^2-2x-1
divide by x^2
x^2-1/x^2-1-2/x

Answer 91

x^2-1/x^2=(x-1/x)(x+1/x)

Answer 92

x-1/x=1

Answer 93

x+1/x-1-2/x=x-1-1/x

Answer 94

x-1/x=1
1-1=0

Answer 95

rosy got it ??

Answer 96

no we didnt get it i think

Answer 97

@ganeshie8

Answer 98

its hard to go through above work as so much was done above, but it seems u had a very good start in killing the denominator