Question

i)find the first 3 terms in ascending powers of x in the expansion (1+x)^5
the coefficient of x^2 in the expansion of (1+(px+x^2))^5 is 95 use your answer in i to find the value of the constant p

Answer 1

(1+x)^5=1+5x+10x^2

Answer 2

@ganeshie8

Answer 3

how can i find the value of constant p

Answer 4

(1+(px+x^2))^5 = 1 + 5(px+x^2) + 10(px+x^2)^2 + ..

right ?

Answer 5

shoudnt it be 1+5(px)^4*x^2)

Answer 6

oh you are right

Answer 7

sorry for that

Answer 8

1+5px+5x^2+10p^2x^2+20px^2+10x^4

Answer 9

20px^3

Answer 10

10p^2+5=95 p>0 p=3

Answer 11

What does "first terms" mean? To me, there is no difference between x^5 or 1 as being the first term.

Answer 12

first 3 terms of a bionomial expansion from 1^5 on towards(5,5) (x)^5