Question

a curve has equation 12/3-2x i) find dy/dx a point moves along this curve. As the point passes through A, the x-coordinate is increasing at a rate of 0.15 units per second and the y-coordinate is increasing at a rate of 0.4 units per second find the possible coordinates of A

Answer 1

dy/dx=-12/(3-2x)^2

Answer 2

that is a complex function correct?

Answer 3

That's a rate of Change Differentiation

Answer 4

question

Answer 5

12/3-2x i
^
it has an imaginary component right?

Answer 6

or thats just i) to indicate part 1 of a set of questions

Answer 7

dy/dx=8/3

Answer 8

y = 12/3-2x

y (3-2x)= 12

3y-2xy= 12

3y' - 2x'y - 2xy'= 0

3(.4) - 2(.15)y - 2(.4)x= 0

1.2 - .3y - .8x= 0

12 = 3y + 8x

Answer 9

i guess my derivative is incorrect

Answer 10

yours was: dy/dx=-12/(3-2x)^2

you forgot a chain rule, multiply by -2

Answer 11

12(3-2x)^-1=-2(-12)/(3-2x)^2

Answer 12

thats better yes, so

40/15 = 24/(3-2x)^2

Answer 13

i solve x=3 or 0

Answer 14

yes

Answer 15

thanks :)

Answer 16

yw