Question

Vector Question

Answer 1

@ganeshie8

Answer 2

which question ?

Answer 3

7

Answer 4

start something like below :

AM = AO + OM
= AO + OX/2
= AO + (OD+DX)/2
= ...

Answer 5

AM=OM-OA i guess OM(0,4j,5k)

Answer 6

looks perfect!

Answer 7

AM=(0,4j,5k)-(8i,0,0))=(-8i,4j,5k)

Answer 8

AC=OC-OA=(0,8j,0)-(8i,0,0)=-8i,8j,0

Answer 9

hey wait, AM doesn't look correct

Answer 10

how did u get OM(0,4j,5k) ?

Answer 11

i said that M is half the distance from D

Answer 12

notice that OM also has x component

Answer 13

AM = AO + OM
= AO + OX/2
= AO + (OD+DX)/2
= (-8,0,0) + [(4,4,0) + (0,0,10) ]/2
= (-8,0,0) + [(4,4,10)]/2
= (-6,2,5)

Answer 14

Oh i understand i will try out AC by myself AC=OC-OA
=(0,8j,0)-(8i,0,0)=(-8i,8j,0)

Answer 15

looks good !!

Answer 16

MAC=AM*AC=(-8*-6)+(2*8)+(5*0)=64 Cos(x)=64/((-6)^2+(2)^2+(5)^2)^1/2*((-8)^2+(8)^2)^1/2=0.701=45.44