Question

can someone help me real quick? medal and fan

Answer 1

Triangle ABC has been rotated 90° to create triangle DEF. Using the image below, prove that perpendicular lines have opposite and reciprocal slopes. You must show all of your work to receive credit.

Answer 2

Given that triangle DEF is formed from triangle ABC rotated 90 degrees, this must mean that EF is perpendicular (oriented at 90 degrees) to BC.
From the diagram, we have: Slope of EF = [-1-(-4)]/(2-5) = -1
Slope of BC = (5-2)/(4-1) = 1
Hence, the slope of BC is the negative reciprocal of the slope of EF.

Answer 3

You can find the slope between (2, -1) and (5, -4) and the slope between (1, 2) and (4, 5).

Answer 4

@alexismcnab You copied that from somewhere.

Answer 5

So? I asked a friend and thy sent it to me. It doesn't matter. If it's right then it's right

Answer 6

Slope between (2, -1) and (5, -4):

\(m = \dfrac{y_2-y_1}{x_2-x_1}\)

\(m = \dfrac{-4 + 1}{5-2}\)

\(m = \dfrac{-3}{3}\)

\(m = -1\)

So the slope between (2, -1) and (5, -4) is -1.

Slope between (1, 2) and (4, 5):

\(m = \dfrac{y_2-y_1}{x_2-x_1}\)

\(m = \dfrac{5-2}{4-1}\)

Can you do the rest to find the slope between (1, 2) and (4, 5)?

Answer 7

i just really have no clue what to put as a answer. i really don't know what what be a good answer.

Answer 8

math is not my subject..

Answer 9

@alexismcnab There's nothing wrong with copying an answer from some other place, but you have to at least give the link to where you got it from.

Answer 10

\(m = \dfrac{5-2}{4-1}\)

\(m = \dfrac{3}{3}\)

\(m = 1\)

So the slope between (1, 2) and (4, 5) is 1.

Since -1 is the opposite of 1, you have proven that perpendicular lines have opposite and reciprocal slopes.

Answer 11

Do you understand? @Para_phrenic88

Answer 12

well im trying to lol

Answer 13

how would i prove that?