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OpenStudy (anonymous):
what would be the pH if 5.00 mL 0.0095M HCl were added to 235.0 mL dH20?
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OpenStudy (cuanchi):
1) first you have to calculate the concentration of the acid after the dilution C1 xV1= C2 xV2 2) it is a strong acid and will dissociate completely, then the concentration of [H+] is going to be equal to the concentration of the acid. 3) then calculate the pH with that concentration with the pH = -log[H+]
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