Question

Indicate the equation of the given line in standard form.

The line containing the diagonal of a square whose vertices are A(-3, 3), B(3, 3), C(3, -3), and D(-3, -3). Find two equations, one for each diagonal.

Answer 1

ok start by finding slope using the formula (y2-y1) / (x2-x1)

Answer 2

do i find the slope between each of the vertices?

Answer 3

exactly....

Answer 4

i got 0/6
i feel like that isn't right.

Answer 5

substituting A (-3,3) for (x1,y1) and C (3,-3) for (x2,y2) you get,
(3-(-3)) / (-3-3) = 6/(-6) = -1

so the slope of the first line is -1

Answer 6

now use this formula,
(y-y1) = m (x-x1)

where (x1,y1) is a point on the line and "m" is the slope.
(y-3) = (-1) * (x-(-3))

y-3 = -1 (x+3)

y-3 = -x-3

Answer 7

you will get x+y = 0 . similarly do for rest
second line (B to D).

first find the slope again using the same formula. you do this by using the formula (y2-y1) / (x2-x1) where (x1,y1) is one point on the line and (x2,y2) is another point on the line.

so substituting B (3,3) for (x1,y1) and D (-3,-3) for (x2,y2) you get:

(-3-3) / (-3-3) = (-6) / (-6) = 1

so the slope of the second line is 1

Answer 8

(y-y1) = m (x-x1)
so using point B (3,3) for (x1,y1) and -1 for "m" you get:

(y-3) = 1* (x-3)

y-3 = x-3
-x + y = 0

It's DONE ;) @aleishealarson

Answer 9

x+y = 0 and -x + y = 0
Hope it helps a bit ^_^

Answer 10

thank you so much!!! xxx

Answer 11

always a pleasure :) :P @aleishealarson