Please help I am in a hurry!!!!!!! In the equilibrium system below, which of the following changes would cause the equilibrium position to shift to the right? CO(g) + 3H2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CH4 (g) + H2O (g) delta H = -206 kJ/mol decreasing the concentration of hydrogen gas (H2) lowering the temperature of the reaction decreasing the concentration of carbon monoxide (CO) increasing the volume of the reaction system
According to Le Chatelier, the position of equilibrium will move so that the concentration of A increases again. That means that more CH4 and H2O will react to replace the A that has been removed. The position of equilibrium moves to the left. same thing when we decrease the concentration of H2 The equilibrium will move in such a way that the temperature increases again.The reaction will tend to heat itself up again to return to the original temperature. It can do that by favouring the exothermic reaction. more of CO and H2 are converted to CH4 and H2O and equilbrium will shift to the right.
lowering temperature....
Thank you!!!
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