Part A: Explain why we do not measure the rate at which a sprinkler waters a lawn in cubic feet per minute? In your explanation, use reasoning based on appropriate units to model this situation. (5 points)

Part B: What are the two quantities that should be measured to find the rate at which a sprinkler waters a lawn? Explain how the rate can be determined. (5 points)

Question

Part A: Explain why we do not measure the rate at which a sprinkler waters a lawn in cubic feet per minute? In your explanation, use reasoning based on appropriate units to model this situation. (5 points)

Part B: What are the two quantities that should be measured to find the rate at which a sprinkler waters a lawn? Explain how the rate can be determined. (5 points)

anonymous · Answer

help

anonymous · Answer

OKAY I KNOW PART B

Part B: By definition, the two quantities are volume and time. In practice the speed of flow is measured through a pipe of known diameter and that reading is translated to volume per time using whatever units the user considers convenient.

anonymous · Answer

lets me try to figure out art a

anonymous · Answer

are u sure what is part b

anonymous · Answer

lol okay my sister did this so she told me the answer

anonymous · Answer

okay

anonymous · Answer

okay for part A

anonymous · Answer

okay so the part B was wrong srry

anonymous · Answer

Part A: The reason why you wouldn't measure the rate at which a sprinkler waters a lawn in cubic feet per minute is you aren't trying to fill a 3 dimensional space. The term cubic refers to 3, 3 dimensions. You use the term cubic when you're measuring volume. In this case we are measuring the rate at which water is sprayed out onto a 2 dimensional surface. A better way to announce this ratio could be: feet per minute, instead of cubic feet per minute. 
For example, let's say that a 5 by 5 area of the lawn is sprinkled with water every minute. That's a ratio of 5 squared feet per minute.

anonymous · Answer

Part B: 
The two quantities that should be measured to find the rate at which a sprinkler waters a lawn are, squared feet and minutes. x squared feet per minute. 
Let's make a real life scenario out of this expression... 
Let's say that the sprinkler sprays water in a semi circle. The radius of this semi circle measures 6 feet. Now let's find the area of the semi circle. 
A= πr [A= (3.14)(r)] 
A= (3.14)(6) 
A= 18.84 
So, the area of the semi circle is 18.84 feet. Now to form the ratio... 
We know that the sprinkler is able to cover an area of 18.84 feet in 1 minute, so let's make this our ratio. 
Every 1 minute(s) the sprinkler waters 18.84 feet of lawn. 
18.84 feet per 1 minute.

anonymous · Answer

do u do home shooling

anonymous · Answer

yes what is for part b is the firts one

anonymous · Answer

nope the second one 
srry the first one was worng

anonymous · Answer

cool thanks

anonymous · Answer

np