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Algebra
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Let f(x) = x2 + 6 and g(x) = x+8/x Find ( g o f)(-7)
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f(x) = x2 + 6 and g(x) = x+8/x f o g is basically putting the g(x) equation into the f(x) equation and x is -7 so f(x) = (x+8/x)^2 + 6 f(-7) = (-7 + 8/-7)^2 +6 = (-7 + -1.14)^2 +6 = (-8.14)^2 +6 = 66.2596 +6 = 72.2596
ok i get that part. but its not one of my answers
what are the possible answers? do they have variables in them?
295/49 384/7 -57/7 63-55
63/55
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oh. its 63/55 I misread your question. g(x) = x+8/x should look like (x+8)/x basically you plug in -7 into f(x) and then take the answer and plug it in for every x in g(x)
oh ok
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