Question

IN DESPERATE NEED OF HELP!!

Answer 1

Find a relationship between a and b so that f is continuous at x = 2.

Answer 2

please please please @jdoe0001

Answer 3

substitute in 2 for x and set ax^2+bx=5x-10
4a+2b=10-10, so 4a+2b=0
Which gives 2b=-4a, or 4a=-2b, and to simplify even further, -2a=b or a=-0.5b

Answer 4

can someone check my work?! MEDAL AND FAN!!

Answer 5

f(x) = 5x - 10 for x >= 2
At x = 2: f(x) = 5*2 - 10 = 10 - 10 = 0

f(x) = ax^2 + bx for <= x < 2
The left side limit of f(x) as x->2- is a(2)^2 + b(2) = 4a + 2b

In order for f(x) to be continuous at x = 2, the left and right side limits must be the same.

4a + 2b = 0
2a + b = 0

Answer 6

oh we got diferent answers...

Answer 7

hmm

Answer 8

where did you get 2a+b from?

Answer 9

4a + 2b = 0
divide by 2:
2a + b = 0

Answer 10

gotchaa

Answer 11

thanks!

Answer 12

you are welcome.